Practice Example #1B: 255.255.128.0 (/17)
Written on 11:34 by Ahmet Emir
- Subnets? 21 = 2 (same as Class C).
- Hosts? 215 – 2 = 32,766 (7 $.25 in the third octet, and 8 in the fourth).
- Accurate subnets? 256 – 128 = 128. 0, 128. Remember that subnetting is performed in the
172.16.0.0 = Arrangement address
255.255.128.0 = Subnet mask
third octet, so the subnet numbers are absolutely 0.0 and 128.0, as apparent in the abutting table.
These are the exact numbers we acclimated with Class C; we use them in the third octet and add
a 0 in the fourth octet for the arrangement address.
- Broadcst abode for anniversary subnet?
- Accurate hosts?
The afterward table shows the two subnets available, the accurate host range, and the broadcast
address of each:
Okay, apprehension that we aloof added the fourth octet’s everyman and accomplished ethics and came up
with the answers. And again, it’s done absolutely the aforementioned way as for a Class C subnet. We just
use the aforementioned numbers in the third octet and added 0 and 255 in the fourth octet—pretty simple
huh! I absolutely can’t say this enough: It’s aloof not hard; the numbers never change; we aloof use
them in altered octets!
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