Practice Example #2B: 255.255.192.0 (/18)
Written on 11:35 by Ahmet Emir
- Subnets? 22 = 4.
- Hosts? 214 – 2 = 16,382 (6 $.25 in the third octet, and 8 in the fourth).
- Accurate subnets? 256 – 192 = 64. 0, 64, 128, 192. Remember that the subnetting is performed
- Broadcast abode for anniversary subnet?
- Accurate hosts?
172.16.0.0 = Network address
255.255.192.0 = Subnet mask
in the third octet, so the subnet numbers are absolutely 0.0, 64.0, 128.0, and 192.0,
as apparent in the abutting table.
Subnet 0.0 128.0
First host 0.1 128.1
Last host 127.254 255.254
Broadcast 127.255 255.255
Subnetting Basics 129
The afterward table shows the four subnets available, the accurate host range, and the broadcast
address of each:
Again, it’s appealing abundant the aforementioned as it is for a Class C subnet—we aloof added 0 and 255 in
the fourth octet for anniversary subnet in the third octet.
Subnet 0.0 64.0 128.0 192.0
First host 0.1 64.1 128.1 192.1
Last host 63.254 127.254 191.254 255.254
Broadcast 63.255 127.255 191.255 255.255
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